Sewage flow calculation | How to calculate the daily treatment capacity, daily design flow rate, and maximum design capacity of a sewage treatment plant

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1. Sewage underground flow monitoring

2. How to calculate the sewage specific flow rate? First of all, may I ask what the "water intake index" refers to? Your data has no units. Based on the size of this data and the "Design Standard for Outdoor Water Supply" GB50013-2018, I speculate that the highest daily comprehensive domestic water quota is 0.35 cubic meters per person per day? If so, the calculation method for the area to flow ratio of sewage should be: 0.35 x population density x 0.85 x 1.1 ÷ 1.2. According to the formula I provided, lets not consider the issue of unit conversion for now. Let me explain why we need to list the calculation formula in this way. × 0.85 refers to the conversion of 85% of water supply into sewage, × 1.1 refers to the additional consideration of 1% of groundwater infiltration, ÷ 1.2 is because according to the definition, the sewage area ratio flow rate refers to the average daily average hourly situation, so the highest daily sewage flow rate divided by the daily variation coefficient is the average daily average hourly flow rate. Of course, if the data of 0.35 for bent and scattered fruits is the average daily comprehensive water quota for production and storage, then the data of 1.2 is redundant. So you still lack data on the population density of the Mu family. The specific formula for sewage specific flow rate is shown in the following figure.

3. How to calculate the daily treatment capacity of a sewage treatment plant, the daily design flow rate, and the maximum design flow rate

Please refer to the "Design Specification for Outdoor Drainage in Shouting Halls" for the specific calculation process. In general, the treatment capacity=industrial drainage volume+sewage volume+rainwater volume, etc. The calculated flow rate is the average daily seepage section flow rate, and then refer to the manual to determine the coefficient of variation K. K multiplied by the average daily flow rate equals the maximum flow rate.

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